What is the Largest Handgun?
When it comes to handguns, most people think of small, concealable firearms designed for self-defense or target shooting. However, there are some handguns that defy the conventional notion of what a handgun should be. In this article, we’ll explore what the largest handgun is and what makes it stand out from the rest.
What is the Largest Handgun?
The largest handgun is often subjective and can depend on various factors such as caliber, length, and weight. However, according to various sources, the largest handgun is the Desert Eagle Mark XIX.50 AE.
Key Features of the Desert Eagle Mark XIX.50 AE
Here are some key features that make the Desert Eagle Mark XIX.50 AE stand out:
- Caliber:.50 AE (Action Express), which is one of the largest handgun calibers in the world
- Barrel Length: 6 inches (152.4 mm)
- Length: 13.5 inches (342.9 mm)
- Width: 1.5 inches (38.1 mm)
- Height: 6 inches (152.4 mm)
- Weight: 74 oz (2095 grams)
- Magazine Capacity: 7 rounds
- Rate of Fire: Semi-automatic
Why is the Desert Eagle Mark XIX.50 AE Considered the Largest Handgun?
There are several reasons why the Desert Eagle Mark X19.50 AE is considered the largest handgun:
- Large Caliber: The.50 AE caliber is significantly larger than most handgun calibers, which makes the Desert Eagle Mark X19.50 AE stand out from the rest.
- Long Barrel: The 6-inch barrel length is longer than most handguns, which allows for greater accuracy and stability.
- Large Size: The Desert Eagle Mark X19.50 AE is larger than most handguns, with a length of 13.5 inches and a weight of 74 oz.
- Powerful Muzzle Energy: The.50 AE caliber produces significant muzzle energy, which makes it effective for hunting and self-defense.
Other Large Handguns
While the Desert Eagle Mark X19.50 AE is considered the largest handgun, there are other handguns that are also quite large. Here are a few examples:
- FN Five-seveN: A semi-automatic pistol with a 5.7x28mm caliber and a length of 8.5 inches (216.5 mm)
- Glock 20: A semi-automatic pistol with a 10mm caliber and a length of 8.7 inches (221.1 mm)
- Smith & Wesson Model 500: A revolver with a.500 S&W Magnum caliber and a length of 14.5 inches (368.3 mm)
Table: Comparison of Large Handguns
Here is a table comparing some of the key features of the Desert Eagle Mark X19.50 AE and other large handguns:
| Feature | Desert Eagle Mark X19.50 AE | FN Five-seveN | Glock 20 | Smith & Wesson Model 500 |
|---|---|---|---|---|
| Caliber | .50 AE | 5.7x28mm | 10mm | .500 S&W Magnum |
| Barrel Length | 6 inches | 4.7 inches | 4.6 inches | 8.5 inches |
| Length | 13.5 inches | 8.5 inches | 8.7 inches | 14.5 inches |
| Weight | 74 oz | 26.4 oz | 32.6 oz | 64.5 oz |
| Magazine Capacity | 7 rounds | 20 rounds | 15 rounds | 5 rounds |
| Rate of Fire | Semi-automatic | Semi-automatic | Semi-automatic | Revolver |
Conclusion
The Desert Eagle Mark X19.50 AE is considered the largest handgun due to its large caliber, long barrel, and overall size. While it may not be the most practical handgun for everyday carry, it is an impressive piece of firepower that is sure to turn heads. Whether you’re a hunter, a target shooter, or simply a gun enthusiast, the Desert Eagle Mark X19.50 AE is a handgun that is sure to impress.
References
- "Desert Eagle Mark X19.50 AE" by Desert Eagle Arms
- "FN Five-seveN" by FN America
- "Glock 20" by Glock Inc.
- "Smith & Wesson Model 500" by Smith & Wesson
- "Handgun Calibers" by Ballistics by the Inch
